1. Tardigrade
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  3. Chemistry
  4. Calculate the ionic radius of a Cs+ ion, assuming that the cell edge length for CsCl is 0.4123 nm and that the ionic radius of a Cl− ion is 0.181 nm.

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Q. Calculate the ionic radius of a $Cs^+$ ion, assuming that the cell edge length for $CsCl$ is $0.4123\, nm$ and that the ionic radius of a $Cl^−$ ion is $0.181\, nm$.

UPSEEUPSEE 2014States of Matter

Solution:

$r_{ Cs ^{+}}+r_{ Cl ^{-}} =\frac{d_{\text {body }}}{2}=\frac{0.7141}{2}=0.3571\, nm$

$r_{ Cs ^{+}} =0.3571-0.181=0.176\, nm$