Question

Calculate the interionic distance for cesium chloride crystal structure

• A. $\frac{\sqrt{3}a}{2}$
• B. $a$
• C. $\frac{a}{2}$
• D. $\frac{2a}{\sqrt{3}}$

Answer 1

Answer: (A)

As $CsCl$ is having body-centred arrangement of particles, Its body diagonal is $\sqrt{3}a$ ,
Hence the interionic distance is $d=\sqrt{3}a/2$ .