Calculate the heat réquired to convert 3 kg of ice at -12° C kept in a calorimeter to steam at 100° C at atmospheric pressure. Given specific heat capacity of ice =2100 Jkg -1 K -1, specific heat capacity of water =4186 Jkg -1 K -1, latent heat of fusion of ice =3.35 × 105 Jkg -1 and latent heat of steam =2.256 × 106 Jkg -1

Question

Calculate the heat réquired to convert 3 kg of ice at -12° C kept in a calorimeter to steam at 100° C at atmospheric pressure. Given specific heat capacity of ice =2100 Jkg -1 K -1, specific heat capacity of water =4186 Jkg -1 K -1, latent heat of fusion of ice =3.35 × 105 Jkg -1 and latent heat of steam =2.256 × 106 Jkg -1 (A) 8.2 × 106 J (B) 9.1 × 106 J (C) 1.1 × 107 J (D) 2.6 × 107 J

Tardigrade Admin · Accepted Answer

Heat required for 1. ice to go from -12° C to 0° C 2. ice to melt at 0° C 3. ice water to go from 0° C to 100° C 4. ice water to vaporize at 100° C ⇒ Q=(3)(2100)(12)+(3)(3.35 × 105) +(3)(4186)(100)+(3)(2.256 × 106) =9.1 × 106 J

$8.2 \times 1 0^{6} J$

$9.1 \times 1 0^{6} J$

$1.1 \times 1 0^{7} J$

$2.6 \times 1 0^{7} J$

8.2×106J

9.1×106J

1.1×107J

2.6×107J

Heat required for 1. ice to go from −12∘C to 0∘C 2. ice to melt at 0∘C 3. ice water to go from 0∘C to 100∘C 4. ice water to vaporize at 100∘C ⇒Q=(3)(2100)(12)+(3)(3.35×105) +(3)(4186)(100)+(3)(2.256×106) =9.1×106J

$8.2 \times 1 0^{6} J$

$9.1 \times 1 0^{6} J$

$1.1 \times 1 0^{7} J$

$2.6 \times 1 0^{7} J$