Calculate the force required to separate the glass plate of area 10-2m2 with a film of water 0.05 mm thick [surface tension of water is 70× 10-3 N/m] :

Question

Calculate the force required to separate the glass plate of area 10-2m2 with a film of water 0.05 mm thick [surface tension of water is 70× 10-3 N/m] : (A) 25 N (B) 20 N (C) 14 N (D) 28 N

Tardigrade Admin · Accepted Answer

Force required to separate the plates is F=(2TA/d) ??(i) Here: area =10-2m2 Thickness d = 0.05 mm =0.05× 10-3m From equation (i) F=(2× 70× 10-3× 10-2/0.05× 10-3)=28N

Q. Calculate the force required to separate the glass plate of area $10^{- 2} m^{2}$ with a film of water 0.05 mm thick [surface tension of water is $70 \times 10^{- 3}$ N/m] :

25 N

20 N

14 N

28 N

Force required to separate the plates is $F = \frac{2 T A}{d}$ ??(i) Here: area $= 10^{- 2} m^{2}$ Thickness d = 0.05 mm $= 0.05 \times 10^{- 3} m$ From equation (i) $F = \frac{2 \times 70 \times 10 ^{- 3} \times 10 ^{- 2}}{0.05 \times 10 ^{- 3}} = 28 N$

Q. Calculate the force required to separate the glass plate of area 10−2m2 with a film of water 0.05 mm thick [surface tension of water is 70×10−3 N/m] :