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  4. Calculate the force required to separate the glass plate of area 10-2m2 with a film of water 0.05 mm thick [surface tension of water is 70× 10-3 N/m] :

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Q. Calculate the force required to separate the glass plate of area $ {{10}^{-2}}{{m}^{2}} $ with a film of water 0.05 mm thick [surface tension of water is $ 70\times {{10}^{-3}} $ N/m] :

BVP MedicalBVP Medical 2003

Solution:

Force required to separate the plates is $ F=\frac{2TA}{d} $ ??(i) Here: area $ ={{10}^{-2}}{{m}^{2}} $ Thickness d = 0.05 mm $ =0.05\times {{10}^{-3}}m $ From equation (i) $ F=\frac{2\times 70\times {{10}^{-3}}\times {{10}^{-2}}}{0.05\times {{10}^{-3}}}=28N $