Question

Calculate the equivalent weight of $KH{C}_2{O}_4$ when it is oxidised by $Mn{O}_4^{-}$ in basic medium.

• A. 64
• B. 128
• C. 32
• D. 15

Answer 1

Answer: (A)

$H_{2}O+3H{C}_2{O}_4^{-}+2Mn{O}_4^{-}\to 2Mn{O}_2+C{O}_2+5O{H}^{-}$

Eq. wt. of $KH{C}_2{O}_4=\frac{M.wt}{2}=64$