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  4. Calculate the equivalent weight of KHC 2 O 4 when it is oxidised by MnO 4- in basic medium.

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Q. Calculate the equivalent weight of $KHC _{2} O _{4}$ when it is oxidised by $MnO _{4}^{-}$ in basic medium.

Redox Reactions

Solution:

$H _{2} O +3 HC _{2} O _{4}^{-}+2 MnO _{4}^{-} \rightarrow 2 MnO _{2}+ CO _{2}+5 OH ^{-}$

Eq. wt. of $KHC _{2} O _{4}=\frac{ M . wt }{2}=64$