Calculate the emf of half cell: Pt beginarrayl Cl 2( g ) (10 atm ) endarray mid beginarrayl HCl (0.1) M endarray E Cl 2 mid Cl -0=1.36 V

Question

Calculate the emf of half cell: Pt beginarrayl Cl 2( g ) (10 atm ) endarray mid beginarrayl HCl (0.1) M endarray E Cl 2 mid Cl -0=1.36 V (A) 1.45 V (B) 1.27 V (C) -1.45 V (D) -1.27 V

Tardigrade Admin · Accepted Answer

Cl 2 arrow 2 Cl -+2 e - E = E °-(0.0591/ n ) log 10 ([ Cl -]2/ P Cl 2) 1.36-0.059 / 2 log ((0.1)2/10)=1.36-0.0295 ×-3=1.45 V

Q. Calculate the emf of half cell :
$Pt C l_{2} (g) (10 a t m) ∣ H Cl (0.1) M E_{C l_{2} ∣ C l^{-}}^{0} = 1.36 V$

1.45 V

1.27 V

-1.45 V

-1.27 V

$C l_{2} \to 2 C l^{-} + 2 e^{-}$

$E = E^{\circ} - \frac{0.0591}{n} lo g_{10} \frac{[ C l ^{-} ] ^{2}}{P _{C l_{2}}}$

$1.36 - 0.059/2 lo g \frac{( 0.1 ) ^{2}}{10} = 1.36 - 0.0295 \times - 3 = 1.45 V$

Q. Calculate the emf of half cell : PtCl2​(g)(10atm)​∣HCl(0.1)M​ECl2​∣Cl−0​=1.36V