Calculate the density of an aqueous solution of K I if its molarity and molality are 1.44 M and 1.5 mol. kg -1 respectively .

Question

Calculate the density of an aqueous solution of K I if its molarity and molality are 1.44 M and 1.5 mol. kg -1 respectively . (A) 2.20 gL -1 (B) 2.50 gL -1 (C) 1.20 gL -1 (D) 0.50 gL -1

Tardigrade Admin · Accepted Answer

We know, m=(1000 × M/1000 × d-M × MB) ⇒ d=(1000 × M +m × M × MB/1000 × m) =(1000 × 1.44+1.5 × 1.44 × 166/1000 × 1.5) =1.1990=1.20 g L -1 ∵ m = molality =1.5 mol kg -1 M= molarity =1.44 mol L -1 =166 g mol -1 d= density of solution

Q. Calculate the density of an aqueous solution of $K I$ if its molarity and molality are $1.44 M$ and $1.5 m o l . k g^{- 1}$ respectively .

$2.20 g L^{- 1}$

$2.50 g L^{- 1}$

$1.20 g L^{- 1}$

$0.50 g L^{- 1}$

Q. Calculate the density of an aqueous solution of KI if its molarity and molality are 1.44M and 1.5mol.kg−1 respectively .

2.20gL−1

2.50gL−1

1.20gL−1

0.50gL−1

We know, m=1000×d−M×MB​1000×M​ ⇒d=1000×m1000×M+m×M×MB​​ =1000×1.51000×1.44+1.5×1.44×166​ =1.1990=1.20gL−1 ∵m= molality =1.5molkg−1 M= molarity =1.44molL−1 =166gmol−1 d= density of solution

Q. Calculate the density of an aqueous solution of $K I$ if its molarity and molality are $1.44 M$ and $1.5 m o l . k g^{- 1}$ respectively .

$2.20 g L^{- 1}$

$2.50 g L^{- 1}$

$1.20 g L^{- 1}$

$0.50 g L^{- 1}$