Question

Calculate the concentration of $NaOH$ solution in g/ml. which has the same normality as that of a solution of $HCl$ of concentration $0.04g/ml$

• A. $0.0215g/ml$
• B. $0.032g/ml$
• C. $0.48g/ml$
• D. $0.0438g/ml$

Answer 1

Answer: (D)

$N=n\times M$
$M=\frac{no.of.moles}{Vol.in\left(L\right)}=\frac{\frac{0.04}{36}}{10^{-3}}$
$=\frac{1.1\times 10^{-3}}{10^{-3}}=1.1$
$N=1\times 1.1=1.1N$
M of NaoH $=\frac{\frac{x}{40}}{10^{-3}}$
where x is wt. o f NaOH in g.
$1.1\times 10^{-3}=\frac{x}{40}$
$x=4.4\times 10^{-2}$
$=0.044g/ml$