Calculate Kc for the reversible process given below if KP = 167 and T = 800° C CaCO3 (s) leftharpoons CaO(s) + CO2 (g)

Question

Calculate Kc for the reversible process given below if KP = 167 and T = 800° C CaCO3 (s) leftharpoons CaO(s) + CO2 (g) (A) 1.95 (B) 1.85 (C) 1.89 (D) 1.60

Tardigrade Admin · Accepted Answer

Kp =Kc(RT)Δ ng For Eq. CaCO3 (s) leftharpoons CaO(s) + CO2 (g),Δ ng = 1 Kc = (Kp/(RT)Δ ng) = (167/(0.0821 × 1073)1)=1.89

Q. Calculate $K_{c}$ for the reversible process given below if $K_{P} = 167$ and $T = 80 0^{\circ} C$
$C a C O_{3} (s) ⇌ C a O (s) + C O_{2} (g)$

1.95

1.85

1.89

1.60

$K_{p} = K_{c} (RT)^{Δ n_{g}}$
For Eq. $C a C O_{3} (s) ⇌ C a O (s) + C O_{2} (g), Δ n_{g} = 1$
$K_{c} = \frac{K _{p}}{( RT ) ^{Δ} n _{g}}$
$= \frac{167}{( 0.0821 \times 1073 ) ^{1}} = 1.89$

Q. Calculate Kc​ for the reversible process given below if KP​=167 and T=800∘C CaCO3​(s)⇌CaO(s)+CO2​(g)