Calculate dipole moment of the following compound: If textμ textC - textCl= text1.55 Dand textμ textC - textNO2= text3.95 D

Question

Calculate dipole moment of the following compound: <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/c-duudvp50wtlbp6ak.jpg" /> If textμ textC - textCl= text1.55 Dand textμ textC - textNO2= text3.95 D (A) 5.5 D (B) 2.2 D (C) 2.4 D (D) 4.2 D

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/notfound.jpg /> textμ textP textxy=√ textμ textx2 + textμ texty2 + 2 textμ textx textμ texty cos 1 8 0 texto = √ textμ textx2 + textμ texty2 - 2 textμ textx textμ texty = √(( textμ) textx - ( textμ) texty)2 = 3.95 - text1.55 = 2.4 D Alternative solution For para position, μ textmolecule= text3.95- text1.55= text2.40 D

Q. Calculate dipole moment of the following compound:

If $μ_{C - Cl} = 1.55 D an d μ_{C - NO_{2}} = 3.95 D$

5.5 D

2.2 D

2.4 D

4.2 D

$μ_{P_{xy}} = μ_{x}^{2} + μ_{y}^{2} + 2 μ_{x} μ_{y} cos 18 0^{o}$
$= μ_{x}^{2} + μ_{y}^{2} - 2 μ_{x} μ_{y}$
$= ((μ)_{x} - (μ)_{y})^{2}$
$= 3.95 - 1.55$
$= 2.4 D$
Alternative solution
For para position,
$μ_{molecule} = 3.95 - 1.55 = 2.40 D$

Q. Calculate dipole moment of the following compound: If μC−Cl​=1.55 DandμC−NO2​​=3.95 D