Calculate Δ H (in Joules) for, C (graphite) arrow C (diamond), from the following data C ( graphite )+ O 2(g) arrow CO 2(g) ; Δ H =-393.5 kJ C (diamond) + O 2(g) arrow CO 2(g) ; Δ H =-395.4 kJ

Question

Calculate Δ H (in Joules) for, C (graphite) arrow C (diamond), from the following data C ( graphite )+ O 2(g) arrow CO 2(g) ; Δ H =-393.5 kJ C (diamond) + O 2(g) arrow CO 2(g) ; Δ H =-395.4 kJ (A)  1,900  (B)  -788.9× 103  (C)  1,90,000  (D)  + 788.9× 103

Tardigrade Admin · Accepted Answer

C (graphite) + O 2(g) arrow CO 2(g) Δ H =-393.5 kJ ...(i) C (diamond) + O 2(g) arrow CO 2(g) Δ H =-395.4 kJ..(ii) C (graphite) arrow C (diamond); Subtract the Eq (ii) form (i) C (graphite) arrow C (diamond) Δ H=-393.5-(-395.4) =1.9 k J=1900 J

Q. Calculate $Δ H$ (in Joules) for, $C$ (graphite) $\to C$ (diamond), from the following data $C ($ graphite $) + O_{2} (g) \to C O_{2} (g); Δ H = - 393.5 k J C$ (diamond) $+ O_{2} (g) \to C O_{2} (g); Δ H = - 395.4 k J$

$1, 900$

$- 788.9 \times 1 0^{3}$

$1, 90, 000$

$+ 788.9 \times 1 0^{3}$

$C$ (graphite) $+ O_{2} (g) \to C O_{2} (g)$
$Δ H = - 393.5 k J .$ ..(i)
$C$ (diamond) $+ O_{2} (g) \to C O_{2} (g)$
$Δ H = - 395.4 k J$ ..(ii)
$C$ (graphite) $\to C$ (diamond);
Subtract the Eq (ii) form (i)
$C$ (graphite) $\to C$ (diamond)
$Δ H = - 393.5 - (- 395.4)$
$= 1.9 k J = 1900 J$

Q. Calculate ΔH (in Joules) for, C (graphite) →C (diamond), from the following data C( graphite )+O2​(g)→CO2​(g);ΔH=−393.5kJC (diamond) +O2​(g)→CO2​(g);ΔH=−395.4kJ

1,900

−788.9×103

1,90,000

+788.9×103