Calculate Δ H f 0 for chloride ion from the following data: (1/2) H 2( g )+(1/2) Cl 2( g ) arrow HCl ( g ) ; Δ H f ° =-92.4 kJ HCl ( g )+ nH 2 O arrow H +( aq )+ Cl -( aq ) ; Δ H f ° =-74.8 kJ Δ H f 0 of H +( aq )=0.0 kJ

Question

Calculate Δ H f 0 for chloride ion from the following data: (1/2) H 2( g )+(1/2) Cl 2( g ) arrow HCl ( g ) ; Δ H f ° =-92.4 kJ HCl ( g )+ nH 2 O arrow H +( aq )+ Cl -( aq ) ; Δ H f ° =-74.8 kJ Δ H f 0 of H +( aq )=0.0 kJ (A) -167.2 kJ (B) -165.2 kJ (C) -157.2 kJ (D) -147.2 kJ

Tardigrade Admin · Accepted Answer

Given, (1/2) H 2 g + aq arrow H + aq + e - ; Δ H f °=0 kJ ldots . i (1/2) H 2 g +(1/2) Cl 2 g arrow HClg ; Δ H f °=-92.4 kJ ldots ii HClg + nH 2 Ol arrow H + aq + Cl - aq ; Δ H °=-74.8 kJ ldots iii ii + iii - i ∴ (1/2) Cl 2 g + nH 2 O + e - arrow Cl - aq ; Δ H f °=-92.4-74.8 kJ =-167.2 kJ.... iv Heat of formation for Cl -aq =-167.2 kJ

Q. Calculate $Δ H_{f}^{0}$ for chloride ion from the following data:
$\frac{1}{2} H_{2} (g) + \frac{1}{2} C l_{2} (g) \to H Cl (g); Δ H_{f}^{\circ} = - 92.4 k J$
$H Cl (g) + n H_{2} O \to H^{+} (a q) + C l^{-} (a q); Δ H_{f}^{\circ} = - 74.8 k J$
$Δ H_{f}^{0}$ of $H^{+} (a q) = 0.0 k J$

$- 167.2 k J$

$- 165.2 k J$

$- 157.2 k J$

$- 147.2 k J$

Q. Calculate ΔHf0​ for chloride ion from the following data: 21​H2​(g)+21​Cl2​(g)→HCl(g);ΔHf∘​=−92.4kJ HCl(g)+nH2​O→H+(aq)+Cl−(aq);ΔHf∘​=−74.8kJ ΔHf0​ of H+(aq)=0.0kJ

−167.2kJ

−165.2kJ

−157.2kJ

−147.2kJ

Q. Calculate $Δ H_{f}^{0}$ for chloride ion from the following data:
$\frac{1}{2} H_{2} (g) + \frac{1}{2} C l_{2} (g) \to H Cl (g); Δ H_{f}^{\circ} = - 92.4 k J$
$H Cl (g) + n H_{2} O \to H^{+} (a q) + C l^{-} (a q); Δ H_{f}^{\circ} = - 74.8 k J$
$Δ H_{f}^{0}$ of $H^{+} (a q) = 0.0 k J$

$- 167.2 k J$

$- 165.2 k J$

$- 157.2 k J$

$- 147.2 k J$