Calculate Δ H f (in kcal) for the formation of MgS from the Born-Haber cycle given below All the values are in kcal / mol . Δ H f is the enthalpy of formation of MgS ( s ) . IP I and I.P II are first and second I.E. Given 3(I.P 1+ I.P II ) =-19 Δ H f

Question

Calculate Δ H f (in kcal) for the formation of MgS from the Born-Haber cycle given below <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/92620f150b8c4e982781b8ff9498a00e-.png" /> All the values are in kcal / mol . Δ H f is the enthalpy of formation of MgS ( s ) . IP I and I.P II are first and second I.E. Given 3(I.P 1+ I.P II ) =-19 Δ H f  (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

For Born - Harber cycle of Mgs Δ H f =133.2+(-(19/3) Δ H f )+(36.5/8)-72.4-700.2 ∴ Δ H f =-86.6 kcal

Q. Calculate $Δ H_{f}$ (in kcal) for the formation of $M g S$ from the Born-Haber cycle given below

All the values are in $k c a l / m o l .Δ H_{f}$ is the enthalpy of formation of $M g S (s) . I P_{I}$ and I.P $_{II}$ are first and second I.E. Given 3(I.P $_{1} +$ I.P $_{II}$ ) $= - 19Δ H_{f}$

For Born - Harber cycle of $M g s$
$Δ H_{f} = 133.2 + (- \frac{19}{3} Δ H_{f}) + \frac{36.5}{8} - 72.4 - 700.2$
$∴ Δ H_{f} = - 86.6 k c a l$

Q. Calculate ΔHf​ (in kcal) for the formation of MgS from the Born-Haber cycle given below All the values are in kcal/mol.ΔHf​ is the enthalpy of formation of MgS(s).IPI​ and I.P II​ are first and second I.E. Given 3(I.P 1​+ I.P II​ ) =−19ΔHf​

For Born - Harber cycle of Mgs ΔHf​=133.2+(−319​ΔHf​)+836.5​−72.4−700.2 ∴ΔHf​=−86.6kcal

Q. Calculate $Δ H_{f}$ (in kcal) for the formation of $M g S$ from the Born-Haber cycle given below

All the values are in $k c a l / m o l .Δ H_{f}$ is the enthalpy of formation of $M g S (s) . I P_{I}$ and I.P $_{II}$ are first and second I.E. Given 3(I.P $_{1} +$ I.P $_{II}$ ) $= - 19Δ H_{f}$

For Born - Harber cycle of $M g s$
$Δ H_{f} = 133.2 + (- \frac{19}{3} Δ H_{f}) + \frac{36.5}{8} - 72.4 - 700.2$
$∴ Δ H_{f} = - 86.6 k c a l$