Cp and Cv are specific heats at constant pressure and constant volume respectively. It is observed that Cp-Cv = a for hydrogen gas Cp-Cv = b for nitrogen gas The correct relation between a and b is :

Question

Cp and Cv are specific heats at constant pressure and constant volume respectively. It is observed that Cp-Cv = a for hydrogen gas Cp-Cv = b for nitrogen gas The correct relation between a and b is : (A) a = (1/14) b  (B) a = b  (C) a = 14 b  (D) a = 28 b

Tardigrade Admin · Accepted Answer

Let molar heat capacity at constant pressure =

X_{p}

and molar heat capacity at constant volume =

X_{v}

X_{p} - X_{v} = R

M C_{p} - M C_{v} = R

C_{p} - C_{v} = \frac{R}{M}

For hydrogen;

a = \frac{R}{2}

For

N_{2}; b = \frac{R}{28}

\frac{a}{b} = 14

a = 14 b

Q. $C_{p}$ and $C_{v}$ are specific heats at constant pressure and constant volume respectively.
It is observed that
$C_{p} - C_{v}$ = a for hydrogen gas
$C_{p} - C_{v}$ = b for nitrogen gas
The correct relation between $a$ and $b$ is :

$a = \frac{1}{14} b$

$a = b$

$a = 14 b$

$a = 28 b$

Let molar heat capacity at constant pressure = $X_{p}$
and molar heat capacity at constant volume = $X_{v}$
$X_{p} - X_{v} = R$
$M C_{p} - M C_{v} = R$
$C_{p} - C_{v} = \frac{R}{M}$
For hydrogen; $a = \frac{R}{2}$
For $N_{2}; b = \frac{R}{28}$
$\frac{a}{b} = 14$
$a = 14 b$

Q. Cp​ and Cv​ are specific heats at constant pressure and constant volume respectively. It is observed that Cp​−Cv​ = a for hydrogen gas Cp​−Cv​ = b for nitrogen gas The correct relation between a and b is :

a=141​b

a=b

a=14b

a=28b