The value of Δ H for cooling 2 mole of an ideal monoatomic gas from 225° C to 125° C at constant pressure will be [given .Cp=(5/2) R]

Question

The value of Δ H for cooling 2 mole of an ideal monoatomic gas from 225° C to 125° C at constant pressure will be [given .Cp=(5/2) R] (A) 250 R (B) -500 R (C) 500 R (D) -250 R

Tardigrade Admin · Accepted Answer

Δ H=-n Cp Δ T =-2 × (5/2) R(225-125) =-5 R(100)=-500 R

Q. The value of $Δ H$ for cooling $2$ mole of an ideal monoatomic gas from $22 5^{\circ} C$ to $12 5^{\circ} C$ at constant pressure will be [given $C_{p} = \frac{5}{2} R]$

250 R

-500 R

500 R

-250 R

$Δ H = - n C_{p} Δ T$
$= - 2 \times \frac{5}{2} R (225 - 125)$
$= - 5 R (100) = - 500 R$

Q. The value of ΔH for cooling 2 mole of an ideal monoatomic gas from 225∘C to 125∘C at constant pressure will be [given Cp​=25​R]