CH3-CH2-O-CH2-CH3 reacts with hot and excess HI, then formed product is:

Question

CH3-CH2-O-CH2-CH3 reacts with hot and excess HI, then formed product is: (A)  CH3-CH2-I and CH3CH2OH  (B)  CH3-CH2-OH  (C)  CH3-CH2-I  (D) none of the above

Tardigrade Admin · Accepted Answer

Ether on reaction with excess of HI produce two molecules of alkyl halide <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/aa311da2374029bdec4130c57100cb79-.png" /> When equimolar quantities of ether and HI are present, then one molecule of alkyl halide and one molecule of alcohol are formed.

Q. $C H_{3} - C H_{2} - O - C H_{2} - C H_{3}$ reacts with hot and excess $H I$ , then formed product is:

$C H_{3} - C H_{2} - I$ and $C H_{3} C H_{2} O H$

$C H_{3} - C H_{2} - O H$

$C H_{3} - C H_{2} - I$

none of the above

Ether on reaction with excess of $H I$ produce two molecules of alkyl halide

When equimolar quantities of ether and $H I$ are present, then one molecule of alkyl halide and one molecule of alcohol are formed.

Q. CH3​−CH2​−O−CH2​−CH3​ reacts with hot and excess HI, then formed product is:

CH3​−CH2​−I and CH3​CH2​OH

CH3​−CH2​−OH

CH3​−CH2​−I