CH3CH2COOH xrightarrow[Fe]Cl2X xrightarrowalc. KOHY, the compound Y is:

Question

CH3CH2COOH xrightarrow[Fe]Cl2X xrightarrowalc. KOHY, the compound Y is: (A)  CH2==CHCOOH  (B)  CH2CHClCOOH  (C)  CH3CH2CN  (D)  CH3CH2OH

Tardigrade Admin · Accepted Answer

Propanoic acid, on treatment with halogen, in presence of catalyst, gives a-halo derivative. Thus, the complete reaction is as follows CH3.CH2COOH xrightarrow[Fe]Cl2 CH3- overset beginsmallmatrix Cl | endsmallmatrix mathopC H.COOH xrightarrow[ textDehydrodehalogenation] textalc text. textKOH underset textAcrylic textacid mathopCH2==CH⋅ COOH Hence, the product is acrylic acid.

Q. $C H_{3} C H_{2} COO H C l_{2} F e X a l c . K O H Y,$ the compound $Y$ is:

$C H_{2} == C H COO H$

$C H_{2} C H ClCOO H$

$C H_{3} C H_{2} CN$

$C H_{3} C H_{2} O H$

Q. CH3​CH2​COOHCl2​Fe​Xalc.KOH​Y, the compound Y is:

CH2​==CHCOOH

CH2​CHClCOOH

CH3​CH2​CN

CH3​CH2​OH

Propanoic acid, on treatment with halogen, in presence of catalyst, gives a-halo derivative. Thus, the complete reaction is as follows CH3​.CH2​COOHCl2​Fe​CH3​−CCl∣​H.COOH alc.KOHDehydrodehalogenation​AcrylicacidCH2​==CH⋅COOH​ Hence, the product is acrylic acid.

Q. $C H_{3} C H_{2} COO H C l_{2} F e X a l c . K O H Y,$ the compound $Y$ is:

$C H_{2} == C H COO H$

$C H_{2} C H ClCOO H$

$C H_{3} C H_{2} CN$

$C H_{3} C H_{2} O H$