Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
CH 3 CH 2 C ≡ CH xrightarrow R butanone -2 . R is
Q.
C
H
3
C
H
2
C
≡
C
H
R
butanone
−
2.
R
is
2272
226
JIPMER
JIPMER 2005
Aldehydes Ketones and Carboxylic Acids
Report Error
A
H
g
++
/
d
i
l
⋅
H
2
S
O
4
74%
B
K
M
n
O
4
5%
C
K
Cl
O
3
6%
D
K
2
C
r
2
O
7
15%
Solution:
Alkyne change to ketone upon hydrolysis in presence of mercury salt.
C
H
3
C
H
2
C
≡
C
H
H
.
O
H
H
g
2
+
/
H
2
S
O
4
butanone-2
C
H
3
C
H
2
COC
H
3