C6H5NO2 -[Sn/HCl] C6H5X X is identified as:

Question

C6H5NO2 ->[Sn/HCl] C6H5X X is identified as: (A)  NO  (B)  -NH2  (C)  NHOH  (D) none of these

Tardigrade Admin · Accepted Answer

underset textNitrobenzeneC6H5NO2->[Sn/HCl][(H)] undersetAnilineC6H5NH2 Nitrobenzene on reduction with Sn and HCl produce aniline. Hence, X is identified as -NH2 group.

Q. $C_{6} H_{5} N O_{2} Sn / HCl C_{6} H_{5} X$ $X$ is identified as:

$NO$

$- N H_{2}$

$N H O H$

none of these

$Nitrobenzene C_{6} H_{5} N O_{2} Sn / HCl (H) A ni l in e C_{6} H_{5} N H_{2}$
Nitrobenzene on reduction with $S n$ and $H Cl$ produce aniline. Hence, $X$ is identified as $- N H_{2}$ group.

Q. C6​H5​NO2​Sn/HCl​C6​H5​X X is identified as:

NO

−NH2​

NHOH