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  4. C6H5NO2 ->[Sn/HCl] C6H5X X is identified as:

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Q. $C_6H_5NO_2 \ce{->[Sn/HCl]} C_6H_5X $ $ X $ is identified as:

Rajasthan PMTRajasthan PMT 2006

Solution:

$ \underset{\text{Nitrobenzene}}{C_6H_5NO_2}\ce{->[Sn/HCl][(H)]}\underset{Aniline}{C_6H_5NH_2}$
Nitrobenzene on reduction with $ Sn $ and $ HCl $ produce aniline. Hence, $ X $ is identified as $ -NH_{2} $ group.