Question

$C_6{H}_{5}cOOH\underset{(ii)\Delta }{\overset{(i)N{H}_3}{\to }}P\stackrel{NaOBr}{\to }Q\underset{(ii)\text{Heat to}460K}{\overset{(i)Conc.H_{2}S{O}_4}{\to }}R$ 'R' is

• A. sulphanilamide
• B. $p$-bromosulphanilamide
• C. $o$-bromosulphanilic acid
• D. sulphanilic acid

Answer 1

Answer: (D)

Correct answer is (d) sulphanilic acid