C6H5 - CH = CHCHO xrightarrowX C6H5CH = CHCH2OH In the above sequence X can be:

Question

C6H5 - CH = CHCHO xrightarrowX C6H5CH = CHCH2OH In the above sequence X can be: (A)  H2/Ni  (B)  NaBH4  (C)  K2Cr2O7/H+  (D) both [a] and [b]

Tardigrade Admin · Accepted Answer

NaBH4 and LiAlH4 attacks only carbonyl group and reduce it into alcohol group. They do not attack on double bond. underset textCinnamic aldehydeC6H5 - CH = CHCHO xrightarrowNaBH4 underset textCinnamic alcoholC6H5 - CH = CH . CH2OH

Q. $C_{6} H_{5} - C H = C H C H O X C_{6} H_{5} C H = C H C H_{2} O H$ In the above sequence $X$ can be:

$H_{2} / N i$

$N a B H_{4}$

$K_{2} C r_{2} O_{7} / H^{+}$

both [a] and [b]

$N a B H_{4}$ and $L i A l H_{4}$ attacks only carbonyl group and reduce it into alcohol group. They do not attack on double bond.
$Cinnamic aldehyde C_{6} H_{5} - C H = C H C H O N a B H_{4}$
$Cinnamic alcohol C_{6} H_{5} - C H = C H . C H_{2} O H$

Q. C6​H5​−CH=CHCHOX​C6​H5​CH=CHCH2​OH In the above sequence X can be:

H2​/Ni

NaBH4​

K2​Cr2​O7​/H+