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Tardigrade
Question
Chemistry
C 6 H 12 O 6 xrightarrow text Zymase A xrightarrow[Δ] NaOI B + CHI 3 The number of carbon atoms present in the product B is
Q.
C
6
H
12
O
6
Zymase
A
N
a
O
I
Δ
B
+
C
H
I
3
The number of carbon atoms present in the product
B
is _____
400
126
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JEE Main 2022
Biomolecules
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Answer:
1
Solution:
no. of carbon atoms present in
B
is
1