C2H6(g) +3.5O2(g)→2CO2(g) +3H2O(g) S textvap(H2O,ℓ)=x1 cal K-1(boiling point = T1) Δ Hf(H2O, ℓ)=x2 Δ Hf(CO2)= x3 Δ Hf(C2H6)= x4 Hence, Δ H for the reaction is

Question

C2H6(g) +3.5O2(g)→2CO2(g) +3H2O(g) S textvap(H2O,ℓ)=x1 cal K-1(boiling point = T1) Δ Hf(H2O, ℓ)=x2 Δ Hf(CO2)= x3 Δ Hf(C2H6)= x4 Hence, Δ H for the reaction is (A) 2x3 + 3x2 - x4 (B) 2x3 + 3x2 -3x4 + 3x1T1 (C) 2x+ + 3x2 - x4 - 3x1T1 (D) x1T1 + x2 + x3 - x4

Tardigrade Admin · Accepted Answer

H2O(l)→ H2O(g) Δ H textvap =Δ S textvap TB.P=x1T1 Δ Hf(H2O, g)=Δ Hf (H2O, l)+Δ H textvap =x2 +x1T1 Δ H textreaction=2Δ Hf'(CO2,g)+3Δ Hf(H2O, g)-Δ Hf(C2H6,g) =2x3 +3 (x2+ x1T1)- x4=2x3 +3x2 +3x1T1 -x4

Q. $C_{2} H_{6} (g) + 3.5 O_{2} (g) \to 2 C O_{2} (g) + 3 H_{2} O (g)$
$S_{vap} (H_{2} O, ℓ) = x_{1}$ cal $K^{- 1}$ (boiling point $= T_{1}$ )
$Δ H_{f} (H_{2} O, ℓ) = x_{2}$
$Δ H_{f} (C O_{2}) = x_{3}$
$Δ H_{f} (C_{2} H_{6}) = x_{4}$
Hence, $Δ H$ for the reaction is

$2 x_{3} + 3 x_{2} - x_{4}$

$2 x_{3} + 3 x_{2} - 3 x_{4} + 3 x_{1} T_{1}$

$2 x^{+} + 3 x_{2} - x_{4} - 3 x_{1} T_{1}$

$x_{1} T_{1} + x_{2} + x_{3} - x_{4}$

Q. C2​H6​(g)+3.5O2​(g)→2CO2​(g)+3H2​O(g) Svap​(H2​O,ℓ)=x1​ cal K−1(boiling point =T1​) ΔHf​(H2​O,ℓ)=x2​ ΔHf​(CO2​)=x3​ ΔHf​(C2​H6​)=x4​ Hence, ΔH for the reaction is

2x3​+3x2​−x4​

2x3​+3x2​−3x4​+3x1​T1​

2x++3x2​−x4​−3x1​T1​

x1​T1​+x2​+x3​−x4​

H2​O(l)→H2​O(g)ΔHvap​=ΔSvap​TB.P​=x1​T1​ ΔHf​(H2​O,g)=ΔHf​(H2​O,l)+ΔHvap​=x2​+x1​T1​ ΔHreaction​=2ΔHf′​(CO2​,g)+3ΔHf​(H2​O,g)−ΔHf​(C2​H6,g​) =2x3​+3(x2​+x1​T1​)−x4​=2x3​+3x2​+3x1​T1​−x4​

Q. $C_{2} H_{6} (g) + 3.5 O_{2} (g) \to 2 C O_{2} (g) + 3 H_{2} O (g)$
$S_{vap} (H_{2} O, ℓ) = x_{1}$ cal $K^{- 1}$ (boiling point $= T_{1}$ )
$Δ H_{f} (H_{2} O, ℓ) = x_{2}$
$Δ H_{f} (C O_{2}) = x_{3}$
$Δ H_{f} (C_{2} H_{6}) = x_{4}$
Hence, $Δ H$ for the reaction is

$2 x_{3} + 3 x_{2} - x_{4}$

$2 x_{3} + 3 x_{2} - 3 x_{4} + 3 x_{1} T_{1}$

$2 x^{+} + 3 x_{2} - x_{4} - 3 x_{1} T_{1}$

$x_{1} T_{1} + x_{2} + x_{3} - x_{4}$