Question

$C_2{H}_{5}OH\underset{NaOH}{\overset{I_2}{\to }}A\underset{KOH}{\overset{Aqueous}{\to }}B$ In equation given above $A$ and $B$ are respectively

• A. $CH{I}_3$ and $HCOOK$
• B. $CH{I}_3$ and $C{H}_{3}COOK$
• C. $C{H}_4$ and $HCOOK$
• D. $CH{I}_3$ and $H_2$

Answer 1

Answer: (A)

$C_2{H}_{5}OH+4I_2+6NaOH\to \underset{Iodoform}{CH{I}_3}$ $+HCOONa+5NaI+5H_{2}O$ $CH{I}_3+3KOH\to \left[H-\underset{\begin{array}{c}|\\ OH\end{array}}{\stackrel{\begin{array}{c}OH\\ |\end{array}}{C}}-OH\right]\stackrel{H_{2}O}{\to }$ $H-\stackrel{\begin{array}{c}O\\ ||\end{array}}{C}-OH$ $H-\stackrel{\begin{array}{c}O\\ ||\end{array}}{C}-OH+KOH\to H-\stackrel{\begin{array}{c}O\\ ||\end{array}}{C}-OK+H_{2}O$