By what percentage should the pressure of a given mass of a gas be increased so as to decrease its volume by 10% at a constant temperature?

Question

By what percentage should the pressure of a given mass of a gas be increased so as to decrease its volume by 10% at a constant temperature? (A) 8.1 % (B) 9.1% (C) 10.1 % (D) 11.1 %

Tardigrade Admin · Accepted Answer

(PV/T) = (P' (90/100)V/T) or (P'/P) = (100/90) = 1+ (10/90) or (P' - P/P) = (10/90) = 11.1 %

Q. By what percentage should the pressure of a given mass of a gas be increased so as to decrease its volume by 10% at a constant temperature?

8.1 %

9.1%

10.1 %

11.1 %

$\frac{P V}{T} = \frac{P ^{'} ( 90/100 ) V}{T}$
or $\frac{P ^{'}}{P} = \frac{100}{90} = 1 + \frac{10}{90}$
or $\frac{P ^{'} - P}{P} = \frac{10}{90} = 11.1%$

Q. By what percentage should the pressure of a given mass of a gas be increased so as to decrease its volume by 10% at a constant temperature?

8.1 %

9.1%

10.1 %

11.1 %

TPV​=TP′(90/100)V​ or PP′​=90100​=1+9010​ or PP′−P​=9010​=11.1%

$\frac{P V}{T} = \frac{P ^{'} ( 90/100 ) V}{T}$
or $\frac{P ^{'}}{P} = \frac{100}{90} = 1 + \frac{10}{90}$
or $\frac{P ^{'} - P}{P} = \frac{10}{90} = 11.1%$