By using only two resistance coils singly, in series or in parallel one should be able to obtain resistances of 3 , 4 , 12 and 16 Ω . The separate resistances of the coil are

Question

By using only two resistance coils singly, in series or in parallel one should be able to obtain resistances of 3 , 4 , 12 and 16 Ω . The separate resistances of the coil are (A) 3 and 4 (B) 4 and 12 (C) 12 and 16 (D) 16 and 3

Tardigrade Admin · Accepted Answer

If we take R 1=4Ω , textR2=12Ω then in series resistance textR = textR1 + textR2 = 4 + 1 2 =16Ω In parallel, resistance R =(4 × 12/4 + 12)=3Ω textSoR 1=4Ω , R2 =12Ω

Q. By using only two resistance coils singly, in series or in parallel one should be able to obtain resistances of $3$ , $4$ , $12$ and $16 Ω$ . The separate resistances of the coil are

$3$ and $4$

$4$ and $12$

$12$ and $16$

$16$ and $3$

If we take $R_{1} = 4Ω$ , $R_{2} = 12Ω$ then in series resistance
$R = R_{1} + R_{2}$
$= 4 + 12$
$= 16Ω$
In parallel, resistance $R = \frac{4 \times 12}{4 + 12} = 3Ω$
$So R_{1} = 4Ω$ , $R_{2} = 12Ω$

Q. By using only two resistance coils singly, in series or in parallel one should be able to obtain resistances of 3 , 4 , 12 and 16Ω . The separate resistances of the coil are

3 and 4

4 and 12

12 and 16

16 and 3