By passing H2S gas in acidified KMnO4 . solution, we get

Question

By passing H2S gas in acidified KMnO4 . solution, we get (A)  K2S  (B)  S  (C)  K2SO3  (D)  MnO2

Tardigrade Admin · Accepted Answer

Reduction of K MnO 4 in acidic solution 2 KMnO 4+3 H 2 SO 4+5 H 2 S arrow K 2 SO 4+2 MnSO 4+8 H 2 O +5 S So, by passing H 2 S gas in acidified KMnO 4 solution we get sulphur.

Q. By passing $H_{2} S$ gas in acidified $K M n O_{4}$ . solution, we get

$K_{2} S$

$S$

$K_{2} S O_{3}$

$M n O_{2}$

Reduction of $K M n O_{4}$ in acidic solution
$2 K M n O_{4} + 3 H_{2} S O_{4} + 5 H_{2} S \to K_{2} S O_{4} + 2 M n S O_{4} + 8 H_{2} O + 5 S$
So, by passing $H_{2} S$ gas in acidified $K M n O_{4}$ solution we get sulphur.

Q. By passing H2​S gas in acidified KMnO4​. solution, we get

K2​S

S

K2​SO3​

MnO2​

Reduction of KMnO4​ in acidic solution 2KMnO4​+3H2​SO4​+5H2​S→K2​SO4​+2MnSO4​+8H2​O+5S So, by passing H2​S gas in acidified KMnO4​ solution we get sulphur.

Q. By passing $H_{2} S$ gas in acidified $K M n O_{4}$ . solution, we get

$K_{2} S$

$S$

$K_{2} S O_{3}$

$M n O_{2}$

Reduction of $K M n O_{4}$ in acidic solution
$2 K M n O_{4} + 3 H_{2} S O_{4} + 5 H_{2} S \to K_{2} S O_{4} + 2 M n S O_{4} + 8 H_{2} O + 5 S$
So, by passing $H_{2} S$ gas in acidified $K M n O_{4}$ solution we get sulphur.