By passing electric current, NaClO3 is converted into NaClO4 according to the following equation Na ClO3 + H2 O - NaClO4 + H2 How many moles of NaClO4 will be formed when three Faradays of charge is passed through NaClO3 ?

Question

By passing electric current, NaClO3 is converted into NaClO4 according to the following equation Na ClO3 + H2 O -> NaClO4 + H2 How many moles of NaClO4 will be formed when three Faradays of charge is passed through NaClO3 ? (A) 0.75 (B) 1.0 (C) 1.5 (D) 3.0

Tardigrade Admin · Accepted Answer

underset(+5)NaClO 3+ H 2 O → underset(+7)NaClO 4+ H 2 2F charges required for give 2 moles of electrons therefore 3F of charge give =(3/2)=15 moles of electrons. Hence, 1.5 moles of NaClO 4 will be formed.

Q. By passing electric current, $N a Cl O_{3}$ is converted into $N a Cl O_{4}$ according to the following equation
$N a Cl O_{3} + H_{2} O - > N a Cl O_{4} + H_{2}$
How many moles of $N a Cl O_{4}$ will be formed when three Faradays of charge is passed through $N a Cl O_{3}$ ?

$0.75$

$1.0$

$1.5$

$3.0$

$(+ 5) N a Cl O_{3} + H_{2} O \to (+ 7) N a Cl O_{4} + H_{2}$

2F charges required for give 2 moles of electrons therefore $3 F$ of charge give $= \frac{3}{2} = 15$ moles of electrons.

Hence, $1.5$ moles of $N a Cl O_{4}$ will be formed.

Q. By passing electric current, NaClO3​ is converted into NaClO4​ according to the following equation NaClO3​+H2​O−>NaClO4​+H2​ How many moles of NaClO4​ will be formed when three Faradays of charge is passed through NaClO3​ ?

0.75

1.0

1.5

3.0