By going through the following reactions find out the amount of polyethylene that would be obtained from 64.1 kg of CaC2. (CaC)2+2H2O arrow Ca(OH)2+C2H2 C2H2+H2 arrow C2H4 nC2H4 arrow CH2 - CH2 n

Question

By going through the following reactions find out the amount of polyethylene that would be obtained from 64.1 kg of CaC2. (CaC)2+2H2O arrow Ca(OH)2+C2H2 C2H2+H2 arrow C2H4 nC2H4 arrow CH2 - CH2 n (A) 7 kg (B) 14 kg (C) 21 kg (D) 28 kg

Tardigrade Admin · Accepted Answer

CaC2 oversetH2 O arrow C2H2 oversetH2 arrow C2H4 64gm oversetgives arrow 28 gm 64.1 kg arrow ?

Q. By going through the following reactions find out the amount of polyethylene that would be obtained from 64.1 kg of CaC₂.
$(C a C)_{2} + 2 H_{2} O \to C a (O H)_{2} + C_{2} H_{2}$
$C_{2} H_{2} + H_{2} \to C_{2} H_{4}$
$n C_{2} H_{4} \to {C H_{2} - C H_{2}}_{n}$

7 kg

14 kg

21 kg

28 kg

$C a C_{2} \to H_{2} O C_{2} H_{2} \to H_{2} C_{2} H_{4}$
$64 g m \to g i v es 28 g m$
$64.1 k g \to ?$

Q. By going through the following reactions find out the amount of polyethylene that would be obtained from 64.1 kg of CaC2. (CaC)2​+2H2​O→Ca(OH)2​+C2​H2​ C2​H2​+H2​→C2​H4​ nC2​H4​→{CH2​−CH2​}n​