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  4. By going through the following reactions find out the amount of polyethylene that would be obtained from 64.1 kg of CaC2. (CaC)2+2H2O arrow Ca(OH)2+C2H2 C2H2+H2 arrow C2H4 nC2H4 arrow CH2 - CH2 n

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Q. By going through the following reactions find out the amount of polyethylene that would be obtained from 64.1 kg of CaC2.
$\left(CaC\right)_{2}+2H_{2}O \rightarrow Ca\left(OH\right)_{2}+C_{2}H_{2}$
$C_{2}H_{2}+H_{2} \rightarrow C_{2}H_{4}$
$nC_{2}H_{4} \rightarrow \left\{CH_{2} - CH_{2}\right\}_{n}$

NTA AbhyasNTA Abhyas 2020

Solution:

$CaC_{2}\overset{H_{2} O}{ \rightarrow } \, C_{2}H_{2}\overset{H_{2}}{ \rightarrow }C_{2}H_{4}$
$64gm\overset{gives}{ \rightarrow } \, 28 \, gm$
$64.1 \, kg \rightarrow ? \, $