Bulb B1(100 W - 250 V) and bulb B2(100 W - 200 V) are connected across 250 V . What is potential drop across B2 ?

Question

Bulb B1(100 W - 250 V) and bulb B2(100 W - 200 V) are connected across 250 V . What is potential drop across B2 ? <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-mgmxtxlyjdkjrdb6.jpg" /> (A) 200 V (B) 250 V (C) 98 V (D) 48 V

Tardigrade Admin · Accepted Answer

Resistance of bulb B1, R1=((250)2/100)= 625 Ω Resistance of bulb B2, R2=((200)2/100)= 400 Ω <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-mgmxtxlyjdkjquvu.jpg" /> VR2= (R2/R1 + R2)× 250=(400/625 + 400)× 250=98 V

Q. Bulb $B_{1} (100 W - 250 V)$ and bulb $B_{2} (100 W - 200 V)$ are connected across $250 V$ . What is potential drop across $B_{2}$ ?

$200 V$

$250 V$

$98 V$

$48 V$

Resistance of bulb $B_{1}, R_{1} = \frac{( 250 ) ^{2}}{100} = 625 Ω$
Resistance of bulb $B_{2}, R_{2} = \frac{( 200 ) ^{2}}{100} = 400 Ω$

$V_{R_{2}} = \frac{R _{2}}{R _{1} + R _{2}} \times 250 = \frac{400}{625 + 400} \times 250 = 98 V$

Q. Bulb B1​(100W−250V) and bulb B2​(100W−200V) are connected across 250V . What is potential drop across B2​ ?

200V

250V

98V

48V