Brakes in truck can produce a maximum retardation of 2ms- 2 . Minimum distance required by truck moving with speed 4ms- 2 for stopping if reaction time of the driver is 0.2sec , is :-

Question

Brakes in truck can produce a maximum retardation of 2ms- 2 . Minimum distance required by truck moving with speed 4ms- 2 for stopping if reaction time of the driver is 0.2sec , is :- (A) 4m (B) 4.2m (C) 4.8m (D) 5.2m

Tardigrade Admin · Accepted Answer

S=utR+(u2/2 a) =4× 0.2+((4)2/2 × 2)=4.8m

Q. Brakes in truck can produce a maximum retardation of $2 m s^{- 2}$ . Minimum distance required by truck moving with speed $4 m s^{- 2}$ for stopping if reaction time of the driver is $0.2 sec$ , is :-

$4 m$

$4.2 m$

$4.8 m$

$5.2 m$

$S = u t_{R} + \frac{u ^{2}}{2 a}$
$= 4 \times 0.2 + \frac{( 4 ) ^{2}}{2 \times 2} = 4.8 m$

Q. Brakes in truck can produce a maximum retardation of 2ms−2 . Minimum distance required by truck moving with speed 4ms−2 for stopping if reaction time of the driver is 0.2sec , is :-

4m

4.2m

4.8m

5.2m