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Q. Brakes in truck can produce a maximum retardation of $2ms^{- 2}$ . Minimum distance required by truck moving with speed $4ms^{- 2}$ for stopping if reaction time of the driver is $0.2sec$ , is :-

NTA AbhyasNTA Abhyas 2020

Solution:

$S=ut_{R}+\frac{u^{2}}{2 a}$
$=4\times 0.2+\frac{\left(4\right)^{2}}{2 \times 2}=4.8m$