Both [ Ni ( CO )4] and [ Ni ( CN )4]2- are diamagnetic. The hybridization of nickel in these complexes, respectively, are

Question

Both [ Ni ( CO )4] and [ Ni ( CN )4]2- are diamagnetic. The hybridization of nickel in these complexes, respectively, are (A) sp 3, sp 3 (B) s p3, d s p2 (C) dsp 2, sp 3 (D) dsp 2, dsp 2

Tardigrade Admin · Accepted Answer

Ni ( CO )4= sp 3 .Ni ( CN )4]2-= dsp 2

Q. Both $[N i (CO)_{4}]$ and $[N i (CN)_{4}]^{2 -}$ are diamagnetic. The hybridization of nickel in these complexes, respectively, are

$s p^{3}, s p^{3}$

$s p^{3}, d s p^{2}$

$d s p^{2}, s p^{3}$

$d s p^{2}, d s p^{2}$

$N i (CO)_{4} = s p^{3}$
$N i (CN)_{4}]^{2 -} = d s p^{2}$

Q. Both [Ni(CO)4​] and [Ni(CN)4​]2− are diamagnetic. The hybridization of nickel in these complexes, respectively, are

sp3,sp3

sp3,dsp2

dsp2,sp3

dsp2,dsp2