Both [Ni(CO)4] and [Ni(CN)4]2- are diamagnetic. The hybridisations of nickel in these complexes respectively, are

Question

Both [Ni(CO)4] and [Ni(CN)4]2- are diamagnetic. The hybridisations of nickel in these complexes respectively, are (A) sp3,sp3  (B) sp3,dsp2  (C) dsp2,sp3 (D) dsp2,dsp2

Tardigrade Admin · Accepted Answer

In Ni(CO)4, Ni is sp3- hybridised while in [Ni(CN)4]2-, Ni2+ is dsp2- hybridised.

Q. Both $[N i (CO)_{4}]$ and $[N i (CN)_{4}]^{2 -}$ are diamagnetic. The hybridisations of nickel in these complexes respectively, are

$s p^{3}, s p^{3}$

$s p^{3}, d s p^{2}$

$d s p^{2}, s p^{3}$

$d s p^{2}, d s p^{2}$

In $N i (CO)_{4}, N i$ is $s p^{3} -$ hybridised while in $[N i (CN)_{4}]^{2 -}, N i^{2 +}$ is $d s p^{2} -$ hybridised.

Q. Both [Ni(CO)4​] and [Ni(CN)4​]2− are diamagnetic. The hybridisations of nickel in these complexes respectively, are

sp3,sp3

sp3,dsp2

dsp2,sp3

dsp2,dsp2