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Chemistry
Bond enthalpies of H2, X2 and HX are in the ratio 2: 1: 2. If enthalpy of formation of HX is -50 kJ mol-1, the bond enthalpy of H2 is
Q. Bond enthalpies of
H
2
,
X
2
and
H
X
are in the ratio
2
:
1
:
2
. If enthalpy of formation of
H
X
is
−
50
k
J
m
o
l
−
1
, the bond enthalpy of
H
2
is
6219
234
BITSAT
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A
100
k
J
m
o
l
−
1
41%
B
300
k
J
m
o
l
−
1
8%
C
200
k
J
m
o
l
−
1
37%
D
400
k
J
m
o
l
−
1
15%
Solution:
2
1
H
2
+
2
1
X
2
→
H
X
Let bond enthalpy of
X
−
X
bond be
x
, then
⇒
2
1
×
2
x
+
2
1
×
x
−
2
x
=
−
50
⇒
x
+
0.5
x
−
2
x
=
−
50
K
J
/
m
o
l
⇒
−
0.5
x
=
−
50
⇒
x
=
−
0.5
−
50
=
100
K
J
/
m
o
l