Benzoyl chloride reacts with benzenamine in the presence of a base to form

Question

Benzoyl chloride reacts with benzenamine in the presence of a base to form (A) Benzamide (B) Hydrobenzamide (C) N-Phenylethanamide (D) N-Phenylbenzamide

Tardigrade Admin · Accepted Answer

underset textBenzoyl chlorideC6H5COCl+ underset textBenzamineC6H5NH2 → underset textN-Phenylbenzamide (Benzanilide) C6H5CONHC6H5+HCl

Q. Benzoyl chloride reacts with benzenamine in the presence of a base to form

Benzamide

Hydrobenzamide

N-Phenylethanamide

N-Phenylbenzamide

$Benzoyl chloride C_{6} H_{5} COCl + Benzamine C_{6} H_{5} N H_{2} \to N-Phenylbenzamide (Benzanilide) C_{6} H_{5} CON H C_{6} H_{5} + H Cl$

Q. Benzoyl chloride reacts with benzenamine in the presence of a base to form

Benzamide

Hydrobenzamide

N-Phenylethanamide

N-Phenylbenzamide

Benzoyl chlorideC6​H5​COCl​+BenzamineC6​H5​NH2​​→N-Phenylbenzamide (Benzanilide)C6​H5​CONHC6​H5​​+HCl

$Benzoyl chloride C_{6} H_{5} COCl + Benzamine C_{6} H_{5} N H_{2} \to N-Phenylbenzamide (Benzanilide) C_{6} H_{5} CON H C_{6} H_{5} + H Cl$