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Q. Benzoyl chloride reacts with benzenamine in the presence of a base to form

Amines

Solution:

$\underset{\text{Benzoyl chloride}}{{C_{6}H_{5}COCl}}+\underset{\text{Benzamine}}{{C_{6}H_{5}NH_{2}}} \to \underset{\text{N-Phenylbenzamide (Benzanilide)}} {{C_{6}H_{5}CONHC_{6}H_{5}}}+HCl$