Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
Benzoic acid is treated with SOCl2 and the product (X) formed is reacted with ammonia to give (Y). (Y) on reaction with Br2 and KOH gives (Z). (Z) in the reaction is
Q. Benzoic acid is treated with
SOC
l
2
and the product
(
X
)
formed is reacted with ammonia to give
(
Y
)
.
(
Y
)
on reaction with
B
r
2
and
K
O
H
gives
(
Z
)
.
(
Z
)
in the reaction is
3305
201
Amines
Report Error
A
aniline
B
chlorobenzene
C
benzamide
D
benzoyl chloride
Solution:
Correct answer is (a) aniline
