Benzene (C6H6, 78 g/mol) and toluene (C7H8, 92 g/mol) form an ideal solution At 60°C the vapour pressure of pure benzene and pure toluene are 0.507 atm and 0.184, respectively. The mole fraction of benzene in a solution of these two chemicals that has a vapour pressure of 0.350 atm at 60°

Question

Benzene (C6H6, 78 g/mol) and toluene (C7H8, 92 g/mol) form an ideal solution At 60°C the vapour pressure of pure benzene and pure toluene are 0.507 atm and 0.184, respectively. The mole fraction of benzene in a solution of these two chemicals that has a vapour pressure of 0.350 atm at 60° (A) 0.514 (B) 0.690 (C) 0.486 (D) 0.190

Tardigrade Admin · Accepted Answer

0.35=0.507 × XB+0.184 × Xt dots (1) XB+Xt=1 dots (2) On solving equations (1) and (2), we get XB=0.514

$0.514$

$0.690$

$0.486$

$0.190$

$0.35 = 0.507 \times X_{B} + 0.184 \times X_{t} \dots (1)$
$X_{B} + X_{t} = 1 \dots (2)$
On solving equations (1) and (2), we get
$X_{B} = 0.514$

0.514

0.690

0.486

0.190

0.35=0.507×XB​+0.184×Xt​…(1) XB​+Xt​=1…(2) On solving equations (1) and (2), we get XB​=0.514

$0.514$

$0.690$

$0.486$

$0.190$

$0.35 = 0.507 \times X_{B} + 0.184 \times X_{t} \dots (1)$
$X_{B} + X_{t} = 1 \dots (2)$
On solving equations (1) and (2), we get
$X_{B} = 0.514$