Beats are produced by two waves given by y1=a sin 200π t and y2=a sin 208π t . The number of beats heard per second is

Question

Beats are produced by two waves given by y1=a sin 200π t and y2=a sin 208π t . The number of beats heard per second is (A) zero (B) one (C) four (D) eight

Tardigrade Admin · Accepted Answer

Given, y1=π sin text 200 text π t This equation comparing with y=a sin 2π x1t Then, n1=100 and y1=a sin 208π t This equation comparing with y=a sin 2π n2t n2=104 Hence, the number of beats =n2-n1 =104-100=4

Q. Beats are produced by two waves given by $y_{1} = a sin 200 π t$ and $y_{2} = a sin 208 π t$ . The number of beats heard per second is

zero

one

four

eight

Given, $y_{1} = π s in 200 π t$ This equation comparing with $y = a sin 2 π x_{1} t$ Then, $n_{1} = 100$ and $y_{1} = a sin 208 π t$ This equation comparing with $y = a sin 2 π n_{2} t$ $n_{2} = 104$ Hence, the number of beats $= n_{2} - n_{1}$ $= 104 - 100 = 4$

Q. Beats are produced by two waves given by y1​=asin200πt and y2​=asin208πt . The number of beats heard per second is

zero

one

four

eight

Given, y1​=πsin200πt This equation comparing with y=asin2πx1​t Then, n1​=100 and y1​=asin208πt This equation comparing with y=asin2πn2​t n2​=104 Hence, the number of beats =n2​−n1​ =104−100=4

Q. Beats are produced by two waves given by $y_{1} = a sin 200 π t$ and $y_{2} = a sin 208 π t$ . The number of beats heard per second is

Given, $y_{1} = π s in 200 π t$ This equation comparing with $y = a sin 2 π x_{1} t$ Then, $n_{1} = 100$ and $y_{1} = a sin 208 π t$ This equation comparing with $y = a sin 2 π n_{2} t$ $n_{2} = 104$ Hence, the number of beats $= n_{2} - n_{1}$ $= 104 - 100 = 4$