Based on VSEPR theory, the number of 90 degree F-Br-F angles in BrF5 is

Question

Based on VSEPR theory, the number of 90 degree F-Br-F angles in BrF5 is (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/15b89d877433c85c347b502492293f46-.jpeg" /> All four planar bonds (F-Br-F) will reduce from 90o to 84.8o after lp - bp repulsion.

Q. Based on $V SEPR$ theory, the number of $90$ degree $F - B r - F$ angles in $B r F_{5}$ is

All four planar bonds $(F - B r - F)$ will reduce from $9 0^{o}$ to $84. 8^{o}$ after $lp - b p$ repulsion.

Q. Based on VSEPR theory, the number of 90 degree F−Br−F angles in BrF5​ is

All four planar bonds (F−Br−F) will reduce from 90o to 84.8o after lp−bp repulsion.

Q. Based on $V SEPR$ theory, the number of $90$ degree $F - B r - F$ angles in $B r F_{5}$ is

All four planar bonds $(F - B r - F)$ will reduce from $9 0^{o}$ to $84. 8^{o}$ after $lp - b p$ repulsion.