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Question
Chemistry
Based on the following thermochemical equations H2O(g) + C (s) → CO(g) + H2 (g); Δ H= 131 kJ CO(g) + 1/2 O2(g)→ CO2(g); Δ H= -2 82 kJ H2(g) + 1/2 O2(g)→ H2O(g); Δ H= - 242 kJ C(s) + O2(g)→ CO2(g); Δ H=X kJ The value of X will be
Q. Based on the following thermochemical equations
H
2
O
(
g
)
+
C
(
s
)
→
CO
(
g
)
+
H
2
(
g
)
;
Δ
H
=
131
k
J
CO
(
g
)
+
1/2
O
2
(
g
)
→
C
O
2
(
g
)
;
Δ
H
=
−
282
k
J
H
2
(
g
)
+
1/2
O
2
(
g
)
→
H
2
O
(
g
)
;
Δ
H
=
−
242
k
J
C
(
s
)
+
O
2
(
g
)
→
C
O
2
(
g
)
;
Δ
H
=
X
k
J
The value of
X
will be
4534
179
Thermodynamics
Report Error
A
−
393
k
J
73%
B
−
655
k
J
17%
C
+
393
k
J
8%
D
+
655
k
J
2%
Solution:
The reaction
C
(
s
)
+
O
2
(
g
)
→
C
O
2
(
g
)
is the result of the addition of the given three reactions
∴
Δ
H
=
X
=
131
+
(
−
282
)
+
(
−
242
)
=
−
393
k
J