Based on the following reactions C(graphite) +O2(.g.) arrow CO2(.g.);Δ H=-394 KJ/mol …(i) 2CO(.g.)+O2(.g.) arrow 2CO2(.g.);Δ H=-569 KJ/mol …(ii) The heat of formation of CO will be

Question

Based on the following reactions C(graphite) +O2(.g.) arrow CO2(.g.);Δ H=-394 KJ/mol …(i) 2CO(.g.)+O2(.g.) arrow 2CO2(.g.);Δ H=-569 KJ/mol …(ii) The heat of formation of CO will be (A) +109.5 kJ (B) +219 kJ (C) -109.5 KJ (D) -219 KJ

Tardigrade Admin · Accepted Answer

EC+EO2 arrow EC O2+394 EC O2=-394 2EC O+EO2 arrow 2EC O2+569 2EC O=2EC O2+569=2EC O2+569 =2× -394+569=-219 ∴ textE textCO text= - text109 text.5 textkJ

Q. Based on the following reactions

C(graphite) $+ O_{2} (g) \to C O_{2} (g); Δ H = - 394$ KJ/mol …(i)

$2 CO (g) + O_{2} (g) \to 2 C O_{2} (g); Δ H = - 569$ KJ/mol …(ii)

The heat of formation of CO will be

+109.5 kJ

+219 kJ

-109.5 KJ

-219 KJ

$E_{C} + E_{O_{2}} \to E_{C O_{2}} + 394$

$E_{C O_{2}} = - 394$

$2 E_{CO} + E_{O_{2}} \to 2 E_{C O_{2}} + 569$

$2 E_{CO} = 2 E_{C O_{2}} + 569 = 2 E_{C O_{2}} + 569$

$= 2 \times - 394 + 569 = - 219$

$∴ E_{CO} = - 109 .5 kJ$

Q. Based on the following reactions C(graphite) +O2​(g)→CO2​(g);ΔH=−394 KJ/mol …(i) 2CO(g)+O2​(g)→2CO2​(g);ΔH=−569 KJ/mol …(ii) The heat of formation of CO will be