B2H6 reacts with (CH3)3N to produce

Question

B2H6 reacts with (CH3)3N to produce (A) BH+3N- (CH3)3  (B)  B2H+6 N- (CH3)2 CH3 . BH3 (C)  (CH3)3 N+ BH3 (D)  BH3 N+ (CH3)2 CH3BH3

Tardigrade Admin · Accepted Answer

When B2H6 reacts with (CH3)3N; underset textTrimethyl amine2(CH3)3N+ underset textDiboraneB2H6-> underset textComplex2(CH3)3 overset+N BH3 in this reaction trimethyl amine, reacts readily with diborane and form a 2(CH3)3 overset+N BH3 complex.

Q. $B X_{2} H X_{6}$ reacts with $(CH X_{3}) X_{3} N$ to produce

$BH X_{3}^{+} N X^{-} (CH X_{3}) X_{3}$

$B X_{2} H X_{6}^{+} N X^{-} (CH X_{3}) X_{2} CH X_{3} \cdot BH X_{3}$

$(CH X_{3}) X_{3} N X^{+} BH X_{3}$

$BH X_{3} N X^{+} (CH X_{3}) X_{2} CH X_{3} BH X_{3}$

When $B_{2} H_{6}$ reacts with $(C H_{3})_{3} N$ ;
$Trimethyl amine 2 (CH X_{3}) X_{3} N +$ $Diborane B X_{2} H X_{6}$ $Complex 2 (CH X_{3}) X_{3} N + BH X_{3}$
in this reaction trimethyl amine, reacts readily with diborane and form a $2 (C H_{3})_{3} N + B H_{3}$ complex.

Q. BX2​HX6​ reacts with (CHX3​)X3​N to produce

BHX3+​NX− (CHX3​)X3​

BX2​HX6+​ NX− (CHX3​)X2​ CHX3​⋅BHX3​

(CHX3​)X3​ NX+ BHX3​

BHX3​ NX+ (CHX3​)X2​ CHX3​BHX3​