Question

$\ce{B2H6}$ reacts with $\ce{(CH3)3N}$ to produce

• A. $\ce{BH^{+}_3N^{-} (CH_3)_3 }$
• B. $\ce{ B_2H^{+}_6 N^{-} (CH_3)_2 CH_3 . BH_3}$
• C. $\ce{ (CH_3)_3 N^{+} BH_3}$
• D. $\ce{ BH_3 N^{+} (CH_3)_2 CH_3BH_3}$

Answer 1

Answer: (C)

When $B_2H_6$ reacts with $(CH_3)_3N$;
$\underset{\text{Trimethyl amine}}{\ce{2(CH3)3N}}+$ $\underset{\text{Diborane}}{\ce{B2H6}}\ce{->}$ $\underset{\text{Complex}}{\ce{2(CH3)3 \overset{+}{N} \,BH3}}$
in this reaction trimethyl amine, reacts readily with diborane and form a $2(CH_3)_3\, \overset{+}{N} \,BH_3$ complex.