BX and BY are the magnetic field at the centre of two coils of two coils X and Y respectively, each carrying equal current. If coil X has 200 turns and 20 cm radius and coil Y has 400 turns and 20 cm radius, the ratio of BX and BY is

Question

BX and BY are the magnetic field at the centre of two coils of two coils X and Y respectively, each carrying equal current. If coil X has 200 turns and 20 cm radius and coil Y has 400 turns and 20 cm radius, the ratio of BX and BY is (A) 1: 1 (B) 1: 2 (C) 2: 1 (D) 4: 1

Tardigrade Admin · Accepted Answer

At centre B = N ((μ0 i /2 R )) B x =200((μ0 i /2 × 20 cm )) B y =400((μ0 i /2 × 20 cm )) ( B x / B y )=(1/2)

Q. $B_{X}$ and $B_{Y}$ are the magnetic field at the centre of two coils of two coils $X$ and $Y$ respectively, each carrying equal current. If coil $X$ has $200$ turns and $20 c m$ radius and coil $Y$ has $400$ turns and $20 c m$ radius, the ratio of $B_{X}$ and $B_{Y}$ is

$1 : 1$

$1 : 2$

$2 : 1$

$4 : 1$

At centre $B = N (\frac{μ _{0} i}{2 R})$
$B_{x} = 200 (\frac{μ _{0} i}{2 \times 20 c m})$
$B_{y} = 400 (\frac{μ _{0} i}{2 \times 20 c m})$
$\frac{B _{x}}{B _{y}} = \frac{1}{2}$

Q. BX​ and BY​ are the magnetic field at the centre of two coils of two coils X and Y respectively, each carrying equal current. If coil X has 200 turns and 20cm radius and coil Y has 400 turns and 20cm radius, the ratio of BX​ and BY​ is

1:1

1:2

2:1

4:1